Asked by Tammy
during a hockey game a puck of mass .3 kg is given an inital speed of 12m/s. it slides 50 m o the ice before stopping. Assume the puck decelerates at a constant rate. what is the coefficient of friction betweent the puck and the ice?
I know that it would be a very small answer since there isn't a lot of friction between ice and an object.
I know that the normal force is equal to F_g which means it equals 3N (.3kg*10m/s^2).
But now i have two unknowns I don't know mu and i don't know F_f.
F_f=mu(F_n)
What am i doing wrong?
I know that it would be a very small answer since there isn't a lot of friction between ice and an object.
I know that the normal force is equal to F_g which means it equals 3N (.3kg*10m/s^2).
But now i have two unknowns I don't know mu and i don't know F_f.
F_f=mu(F_n)
What am i doing wrong?
Answers
Answered by
bobpursley
I would do it with energy
1/2 m v%2= frictionforce*distance
and friction force = mu*mg
solve for mu. Notice mass divide out.
1/2 m v%2= frictionforce*distance
and friction force = mu*mg
solve for mu. Notice mass divide out.
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