Question

In a certain neighborhood, the average number of candies received while trick or treating is 50 with a standard deviation of 12. Isaac received 40 candies, calculate his z-score to the nearest hundredth. (1 point) z = Question 2 Trina trick or treated in the same neighborhood and received 47 pieces of candy.

Answer 1

To calculate Isaac's z-score, you can use the formula for the z-score:

\[
z = \frac{(X - \mu)}{\sigma}
\]

where:

- \(X\) is the value you are examining (Isaac's candies received, which is 40),
- \(\mu\) is the mean (average number of candies, which is 50),
- \(\sigma\) is the standard deviation (which is 12).

Plugging in the values:

\[
z = \frac{(40 - 50)}{12} = \frac{-10}{12} \approx -0.83
\]

Thus, Isaac's z-score, rounded to the nearest hundredth, is:

\[
z \approx -0.83
\]


For Trina, who received 47 pieces of candy, we can calculate her z-score in the same way:

\[
z = \frac{(X - \mu)}{\sigma}
\]

where \(X = 47\).

Now, substituting the values:

\[
z = \frac{(47 - 50)}{12} = \frac{-3}{12} = -0.25
\]

Thus, Trina's z-score, rounded to the nearest hundredth, is:

\[
z \approx -0.25
\]