Question

A cargo ship encounters a storm on the high seas and is delayed by two weeks. Once it reaches its destination, the crew discover that 6 out of the 111 crates of fruit it carried have spoilt during the delay. The crates were being shipped for 15 different customers. The crew decide that the remaining unspoilt crates ought to be divided equally among the customers and that whatever remains can be sold separately.

Answer 1

To solve this problem, we'll start by calculating the number of unspoilt crates after the delay.

1. **Total number of crates:** 111
2. **Spoilt crates:** 6

Now, calculate the number of unspoilt crates:

\[
\text{Unspoilt crates} = \text{Total crates} - \text{Spoilt crates} = 111 - 6 = 105
\]

Next, we need to divide the remaining unspoilt crates equally among the 15 customers.

3. **Number of customers:** 15

Now we divide the number of unspoilt crates by the number of customers to find out how many crates each customer will receive:

\[
\text{Crates per customer} = \frac{\text{Unspoilt crates}}{\text{Number of customers}} = \frac{105}{15} = 7
\]

So, each customer will receive 7 crates.

Next, we need to check if there are any remaining crates after dividing them equally:

\[
\text{Remaining crates} = \text{Unspoilt crates} - (\text{Crates per customer} \times \text{Number of customers}) = 105 - (7 \times 15) = 105 - 105 = 0
\]

Since there are no remaining crates, all 105 unspoilt crates are distributed equally among the customers.

**Summary:**
- Each of the 15 customers receives 7 crates.
- There are no remaining crates to sell separately.