Use the following formula to find the efficiency of energy transfer between the harbor seal (2,500 Kcal) and a polar bear (375 Kcal).

Question

(Energy level transfered to next level)(Total energy input) × 100


(1 point)
Responses

15%
15%

10%
10%

20%
20%

12%

Answer 1

To find the efficiency of energy transfer between the harbor seal and the polar bear, we can use the formula you provided:

\[ \text{Efficiency} = \left( \frac{\text{Energy level transferred to next level}}{\text{Total energy input}} \right) \times 100 \]

In this case:

• The energy input is the energy of the harbor seal, which is 2,500 Kcal.
• The energy transferred to the polar bear is 375 Kcal.

Plugging in the values:

\[ \text{Efficiency} = \left( \frac{375 , \text{Kcal}}{2500 , \text{Kcal}} \right) \times 100 \]

Calculating this:

\[ \text{Efficiency} = \left( \frac{375}{2500} \right) \times 100 = 0.15 \times 100 = 15% \]

Thus, the efficiency of energy transfer is 15%.