Asked by Ms. Sue
History - Spenser, Wednesday, October 10, 2007 at 1:33pm
Find the center and radius of x^2 + y^2 - x + 2y - 3 = 0
Find the center and radius of x^2 + y^2 - x + 2y - 3 = 0
Answers
Answered by
bobpursley
You are looking for the form
(x-h)^2 + (y-k)^2 = r^2
x^2 -x +y^2 + 2y - 3=0
so grouping by perfect squares...
(x^2 -x + 1/4) + (y^2+2y+1)= +3-1/4-1
you do the rest. If you need help, repost.
(x-h)^2 + (y-k)^2 = r^2
x^2 -x +y^2 + 2y - 3=0
so grouping by perfect squares...
(x^2 -x + 1/4) + (y^2+2y+1)= +3-1/4-1
you do the rest. If you need help, repost.
Answered by
Spenser
i don't understand....
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