In a cyclic quadrilateral (a quadrilateral inscribed in a circle), the opposite angles are supplementary. This means that the sum of the measures of opposite angles should equal 180 degrees.
Given that:
- \( m\angle A = 27^\circ \)
- \( m\angle E = 2 \times m\angle A = 2 \times 27^\circ = 54^\circ \)
Now we can find \( m\angle I \) and \( m\angle U \) using the property of cyclic quadrilaterals:
- \( m\angle A + m\angle I = 180^\circ \)
- \( m\angle E + m\angle U = 180^\circ \)
Calculating \( m\angle I \):
\[ m\angle I = 180^\circ - m\angle A = 180^\circ - 27^\circ = 153^\circ \]
Calculating \( m\angle U \):
\[ m\angle U = 180^\circ - m\angle E = 180^\circ - 54^\circ = 126^\circ \]
Thus, we have:
- \( m\angle I = 153^\circ \)
- \( m\angle U = 126^\circ \)
The correct answer is:
\( m\angle I = 153^\circ \) and \( m\angle U = 126^\circ \).