To find the force applied to the baseball, we can use Newton's second law of motion, which states that \( F = m \cdot a \), where:
- \( F \) is the force,
- \( m \) is the mass, and
- \( a \) is the acceleration.
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First, convert the mass of the baseball from grams to kilograms since the standard unit of mass in the SI system is kilograms: \[ m = 145 , \text{g} \times \frac{1 , \text{kg}}{1000 , \text{g}} = 0.145 , \text{kg} \]
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The acceleration given is \( a = 80 , \text{m/s}^2 \).
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Now substitute \( m \) and \( a \) into the formula: \[ F = 0.145 , \text{kg} \times 80 , \text{m/s}^2 \] \[ F = 11.6 , \text{N} \]
Therefore, the force applied by the pitcher to the baseball is 11.6 N.