A particle is moving so that its velocity, v(t) = t-64/t^2 for 2≤t≤6. find the total distance traveled by the particle.

Answer 1

distance= integral v(t) dt for 2 to 6

= INT (t-64/t^2)dt= t^2+64/t

put in the limits 6,2

Answer 2

do you mean

(t-64)/t^2 maybe

or

t - (64/t^2) as you typed it

???

Answer 3

its --> t - (64/t^2)
could you please solve it..

Answer 4

Ok, that is what I did.