The equation \( \text{CH}_4 + 2 \text{O}_2 \rightarrow \text{CO}_2 + 2 \text{H}_2\text{O} \) demonstrates the conservation of mass by showing that the total number of each type of atom is the same on both sides of the equation: there is one carbon atom, four hydrogen atoms, and four oxygen atoms (two from \( \text{O}_2 \), and two from \( \text{H}_2\text{O} \)). Additionally, when you calculate the total atomic mass of the reactants (16 amu from 2 O2 and 12 amu from CH4, totaling 32 amu) and compare it to the products (12 amu from CO2 and 8 amu from 2 H2O, also totaling 32 amu), the mass is conserved, further confirming that matter is neither created nor destroyed in the reaction.
Use the equation and the information in the table to answer the question. CH4 + 2 O2 → CO2 + 2 H2OElement Atomic Mass (amu)hydrogen 1carbon 12oxygen 16In one to two sentences, explain two different ways the equation demonstrates the conservation of mass.
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