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Calculate the average deviation from the mean for the following dataset: {23,24,26,27,28,30,31} . Round your answer to the near...Asked by julian celeste
Calculate the average deviation from the mean for the following dataset: {23,24,26,27,28,30,31}
. Round your answer to the nearest hundredth.(1 point)
The average deviation from the mean is
.
. Round your answer to the nearest hundredth.(1 point)
The average deviation from the mean is
.
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To calculate the average deviation from the mean for the dataset {23, 24, 26, 27, 28, 30, 31}, we first need to find the mean of the dataset.
1. **Calculate the mean**:
\[
\text{Mean} = \frac{\text{Sum of all data}}{\text{Number of data points}}
\]
Sum of the data:
\[
23 + 24 + 26 + 27 + 28 + 30 + 31 = 189
\]
Number of data points:
\[
7
\]
\[
\text{Mean} = \frac{189}{7} = 27
\]
2. **Calculate the absolute deviations from the mean**:
Next, we find the absolute deviations from the mean (27):
\[
|23 - 27| = 4
\]
\[
|24 - 27| = 3
\]
\[
|26 - 27| = 1
\]
\[
|27 - 27| = 0
\]
\[
|28 - 27| = 1
\]
\[
|30 - 27| = 3
\]
\[
|31 - 27| = 4
\]
The absolute deviations are: 4, 3, 1, 0, 1, 3, 4.
3. **Calculate the average of these absolute deviations**:
Sum of absolute deviations:
\[
4 + 3 + 1 + 0 + 1 + 3 + 4 = 16
\]
Now, we divide by the number of data points:
\[
\text{Average Deviation} = \frac{16}{7} \approx 2.285714285714286
\]
Rounding to the nearest hundredth:
\[
\text{Average Deviation} \approx 2.29
\]
Thus, the average deviation from the mean is approximately **2.29**.
1. **Calculate the mean**:
\[
\text{Mean} = \frac{\text{Sum of all data}}{\text{Number of data points}}
\]
Sum of the data:
\[
23 + 24 + 26 + 27 + 28 + 30 + 31 = 189
\]
Number of data points:
\[
7
\]
\[
\text{Mean} = \frac{189}{7} = 27
\]
2. **Calculate the absolute deviations from the mean**:
Next, we find the absolute deviations from the mean (27):
\[
|23 - 27| = 4
\]
\[
|24 - 27| = 3
\]
\[
|26 - 27| = 1
\]
\[
|27 - 27| = 0
\]
\[
|28 - 27| = 1
\]
\[
|30 - 27| = 3
\]
\[
|31 - 27| = 4
\]
The absolute deviations are: 4, 3, 1, 0, 1, 3, 4.
3. **Calculate the average of these absolute deviations**:
Sum of absolute deviations:
\[
4 + 3 + 1 + 0 + 1 + 3 + 4 = 16
\]
Now, we divide by the number of data points:
\[
\text{Average Deviation} = \frac{16}{7} \approx 2.285714285714286
\]
Rounding to the nearest hundredth:
\[
\text{Average Deviation} \approx 2.29
\]
Thus, the average deviation from the mean is approximately **2.29**.
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