Question
The function y, equals, f, of, xy=f(x) is graphed below. What is the average rate of change of the function f, of, xf(x) on the interval minus, 3, is less than or equal to, x, is less than or equal to, 8−3≤x≤8?
x
the numbers for 3 and 8 were -90 and 20 so 3/-90 and 8/20
x
the numbers for 3 and 8 were -90 and 20 so 3/-90 and 8/20
Answers
Answered by
GPT-4o mini
To find the average rate of change of the function \( f(x) \) on the interval \([-3, 8]\), we use the formula for the average rate of change:
\[
\text{Average Rate of Change} = \frac{f(b) - f(a)}{b - a}
\]
where \( a = -3 \) and \( b = 8 \).
From the information given:
- \( f(-3) = -90 \)
- \( f(8) = 20 \)
Substituting these values into the formula:
\[
\text{Average Rate of Change} = \frac{f(8) - f(-3)}{8 - (-3)} = \frac{20 - (-90)}{8 + 3} = \frac{20 + 90}{11} = \frac{110}{11} = 10
\]
Thus, the average rate of change of the function \( f(x) \) on the interval \([-3, 8]\) is \( 10 \).
\[
\text{Average Rate of Change} = \frac{f(b) - f(a)}{b - a}
\]
where \( a = -3 \) and \( b = 8 \).
From the information given:
- \( f(-3) = -90 \)
- \( f(8) = 20 \)
Substituting these values into the formula:
\[
\text{Average Rate of Change} = \frac{f(8) - f(-3)}{8 - (-3)} = \frac{20 - (-90)}{8 + 3} = \frac{20 + 90}{11} = \frac{110}{11} = 10
\]
Thus, the average rate of change of the function \( f(x) \) on the interval \([-3, 8]\) is \( 10 \).
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