To find the area of the triangular sail, we first need to calculate the area of the triangle in George's 1/25 scale drawing, and then scale it up to the actual sail size.
The formula for the area of a triangle is:
\[ \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} \]
In George's drawing, the base of the triangle is 1 foot and the height is 2 feet. Plugging in these values:
\[ \text{Area} = \frac{1}{2} \times 1 , \text{ft} \times 2 , \text{ft} = \frac{1}{2} \times 2 = 1 , \text{square foot} \]
Now, since George's drawing is a 1/25 scale drawing, we must determine the actual dimensions of the sail. The actual dimensions will be:
- Actual height = \(2 , \text{ft} \times 25 = 50 , \text{ft}\)
- Actual base = \(1 , \text{ft} \times 25 = 25 , \text{ft}\)
Now, we use the area formula again for the actual sail dimensions:
\[ \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 25 , \text{ft} \times 50 , \text{ft} \]
Calculating that:
\[ \text{Area} = \frac{1}{2} \times 25 \times 50 = \frac{1}{2} \times 1250 = 625 , \text{square feet} \]
Therefore, the area of the actual sail is:
\[ \boxed{625} , \text{square feet} \]