Question


Hitchhiker's thumb (H) is dominant to no hitchhiker's thumb (h). A woman who does not have hitchhiker's thumb marries a man who is heterozygous for hitchhiker's thumb. What is the probable genotypic ratio of their children? (SC.912.L.16.1)

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1 point
0% Hh: 100% hh
50% Hh: 50% hh
75% Hh: 25% hh
100% Hh: 0% hh

Answers

GPT-4o mini
To determine the probable genotypic ratio of the children from the given parents, we need to consider their genotypes.

- The woman who does not have hitchhiker's thumb has the genotype **hh**.
- The man who is heterozygous for hitchhiker's thumb has the genotype **Hh**.

When these two parents have children, we can set up a Punnett square to predict the genotypes of their offspring:

```
H h
----------------
h | Hh | hh |
----------------
h | Hh | hh |
----------------
```

From the Punnett square, we see the following results for the genotypes of the children:
- 50% Hh (heterozygous with hitchhiker's thumb)
- 50% hh (homozygous without hitchhiker's thumb)

Thus, the probable genotypic ratio of their children is:

**50% Hh : 50% hh**

Therefore, the correct answer is:
**50% Hh: 50% hh**