To find the probability that the sale price of homes is less than $175,000, we can use the properties of the normal distribution.
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Identify the mean and standard deviation:
- Mean (\(\mu\)) = $150,000
- Standard deviation (\(\sigma\)) = $25,000
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Convert the sale price to a z-score: The z-score is calculated using the formula: \[ z = \frac{(X - \mu)}{\sigma} \] where \(X\) is the value we are interested in ($175,000).
Substituting the values: \[ z = \frac{(175,000 - 150,000)}{25,000} = \frac{25,000}{25,000} = 1 \]
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Look up the z-score in the standard normal distribution table or use a calculator. The z-score of 1 corresponds to a cumulative probability of approximately 0.8413.
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Convert the probability to a percentage: \[ 0.8413 \times 100 = 84.13% \]
Therefore, the probability that the sale is less than $175,000 is approximately 84.13%.