Question
Solve. Use 3.14 for pi.
A radio station is allowed by the FCC to broadcast over an area with a radius of 233 mi. How much area is this?
Question content area bottom
Part 1
The area is
enter your response here misquared.
(Simplify your answer. Type an integer or a decimal. Round to the nearest hundredth if needed.)
A radio station is allowed by the FCC to broadcast over an area with a radius of 233 mi. How much area is this?
Question content area bottom
Part 1
The area is
enter your response here misquared.
(Simplify your answer. Type an integer or a decimal. Round to the nearest hundredth if needed.)
Answers
GPT-4o mini
To find the area \( A \) of the circle (the area over which the radio station can broadcast), we can use the formula for the area of a circle:
\[
A = \pi r^2
\]
where \( r \) is the radius of the circle. Here, we're given that the radius \( r = 233 \) miles and \( \pi \approx 3.14 \).
Now, substituting in the values:
\[
A = 3.14 \times (233)^2
\]
First, calculate \( (233)^2 \):
\[
(233)^2 = 54289
\]
Now substitute back into the area formula:
\[
A = 3.14 \times 54289
\]
Next, multiply:
\[
A \approx 170,862.06
\]
So, the area over which the radio station can broadcast is approximately:
\[
\text{Area} \approx 170862.06 \text{ mi}^2
\]
Rounded to the nearest hundredth, the area is:
\[
\text{Area} = 170862.06 \text{ mi}^2
\]
You can enter \( 170862.06 \) as the final answer.
\[
A = \pi r^2
\]
where \( r \) is the radius of the circle. Here, we're given that the radius \( r = 233 \) miles and \( \pi \approx 3.14 \).
Now, substituting in the values:
\[
A = 3.14 \times (233)^2
\]
First, calculate \( (233)^2 \):
\[
(233)^2 = 54289
\]
Now substitute back into the area formula:
\[
A = 3.14 \times 54289
\]
Next, multiply:
\[
A \approx 170,862.06
\]
So, the area over which the radio station can broadcast is approximately:
\[
\text{Area} \approx 170862.06 \text{ mi}^2
\]
Rounded to the nearest hundredth, the area is:
\[
\text{Area} = 170862.06 \text{ mi}^2
\]
You can enter \( 170862.06 \) as the final answer.