To determine whether the graph represents the equation \( y = -13x + 4 \), we first need to check what the y-intercept of this equation is.
The equation \( y = -13x + 4 \) has a y-intercept at \( (0, 4) \) since when \( x = 0 \): \[ y = -13(0) + 4 = 4. \]
The plotted points given in the question are \( (0, 3) \) and \( (3, 2) \). The y-intercept indicated by the graph is \( (0, 3) \), which does not match the y-intercept of the equation \( (0, 4) \).
Additionally, the slope of the line can be calculated using the two points. The slope \( m \) between the points \( (0, 3) \) and \( (3, 2) \) is given by: \[ m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{2 - 3}{3 - 0} = \frac{-1}{3}. \] Since the slope \( -13 \) from the equation is significantly steeper than \( -\frac{1}{3} \), this further indicates that the graph does not represent the given equation.
Given all this information, the appropriate response would be:
No, it is not the correct graph because this graph has a y-intercept of (0, 3).