To find the solution to the system of equations given:
- \( 5x + 3y = 29 \) (Equation 1)
- \( 2x - y = 5 \) (Equation 2)
We can solve this using substitution or elimination. We'll use substitution here.
First, let's solve Equation 2 for \(y\):
\[ 2x - y = 5 \implies y = 2x - 5 \]
Next, we'll substitute \(y\) in Equation 1:
\[ 5x + 3(2x - 5) = 29 \]
Now, simplify the equation:
\[ 5x + 6x - 15 = 29 \]
Combine like terms:
\[ 11x - 15 = 29 \]
Add 15 to both sides:
\[ 11x = 44 \]
Now, divide by 11:
\[ x = 4 \]
Next, substitute \(x = 4\) back into the expression for \(y\):
\[ y = 2(4) - 5 = 8 - 5 = 3 \]
Thus, the solution to the system is \((4, 3)\).
The correct ordered pair is (4, 3).