Question
Yati has 1/4 l of red paint 5/8 l of blue paint and 7/8 l of white paint
What is the total volume of paint that yati has.
How much more blue paint than red paint is there
What is the total volume of paint that yati has.
How much more blue paint than red paint is there
Answers
GPT-4o mini
To find the total volume of paint that Yati has, we'll add together the volumes of red, blue, and white paint.
- Red paint: \( \frac{1}{4} \) l
- Blue paint: \( \frac{5}{8} \) l
- White paint: \( \frac{7}{8} \) l
First, we need to convert \( \frac{1}{4} \) into a fraction with a denominator of 8 so that we can easily add them:
\[
\frac{1}{4} = \frac{2}{8}
\]
Now we can add up the volumes:
\[
\text{Total volume} = \frac{2}{8} + \frac{5}{8} + \frac{7}{8}
\]
Combine the fractions:
\[
\text{Total volume} = \frac{2 + 5 + 7}{8} = \frac{14}{8} = \frac{7}{4} \text{ l} = 1.75 \text{ l}
\]
So, the total volume of paint that Yati has is \( 1.75 \) liters.
Next, let's find out how much more blue paint than red paint there is:
- Volume of blue paint: \( \frac{5}{8} \) l
- Volume of red paint: \( \frac{1}{4} = \frac{2}{8} \) l
Now, subtract the volume of red paint from the volume of blue paint:
\[
\text{Difference} = \frac{5}{8} - \frac{2}{8} = \frac{3}{8} \text{ l}
\]
Thus, there is \( \frac{3}{8} \) liters more blue paint than red paint.
- Red paint: \( \frac{1}{4} \) l
- Blue paint: \( \frac{5}{8} \) l
- White paint: \( \frac{7}{8} \) l
First, we need to convert \( \frac{1}{4} \) into a fraction with a denominator of 8 so that we can easily add them:
\[
\frac{1}{4} = \frac{2}{8}
\]
Now we can add up the volumes:
\[
\text{Total volume} = \frac{2}{8} + \frac{5}{8} + \frac{7}{8}
\]
Combine the fractions:
\[
\text{Total volume} = \frac{2 + 5 + 7}{8} = \frac{14}{8} = \frac{7}{4} \text{ l} = 1.75 \text{ l}
\]
So, the total volume of paint that Yati has is \( 1.75 \) liters.
Next, let's find out how much more blue paint than red paint there is:
- Volume of blue paint: \( \frac{5}{8} \) l
- Volume of red paint: \( \frac{1}{4} = \frac{2}{8} \) l
Now, subtract the volume of red paint from the volume of blue paint:
\[
\text{Difference} = \frac{5}{8} - \frac{2}{8} = \frac{3}{8} \text{ l}
\]
Thus, there is \( \frac{3}{8} \) liters more blue paint than red paint.