To determine which option could be a possible value for the irrational number \( d \) that satisfies \( 6 < d < 7 \), let's evaluate each of the given options:
A. \( \sqrt{6.2} \)
Calculating \( \sqrt{6.2} \):
- \( \sqrt{6.2} \approx 2.49 \), which is not within the range \( 6 < d < 7 \).
B. \( 2\pi \)
Calculating \( 2\pi \):
- \( 2\pi \approx 6.283 \), which is within the range \( 6 < d < 7 \) and is an irrational number.
C. \( \sqrt{13} \)
Calculating \( \sqrt{13} \):
- \( \sqrt{13} \approx 3.61 \), which is not within the range \( 6 < d < 7 \).
D. \( 6\pi \)
Calculating \( 6\pi \):
- \( 6\pi \approx 18.85 \), which is not within the range \( 6 < d < 7 \).
Among the options, the only one that is both an irrational number and falls within the range \( 6 < d < 7 \) is:
B. \( 2\pi \).