Asked by Jameisha
(x^2 + x) + ã(x^2 + x) - 2 = 0
Answers
Answered by
Reiny
Is this supposed to say ...
(x^2+x) + √(x^2+x) - 2 = 0 ?
if so, then let y = √(x^2+x)
your equation becomes
y^2 + y - 2 = 0
(y+2)(y-1) = 0
y = -2 or y = 1
sub back into the substitution and you have two quadratic equations to solve.
e.g
√(x^2 + x) = -2 which of course cannot have a real number solution and
√(x^2+x) = 1
square both sides and proceed from there.
(x^2+x) + √(x^2+x) - 2 = 0 ?
if so, then let y = √(x^2+x)
your equation becomes
y^2 + y - 2 = 0
(y+2)(y-1) = 0
y = -2 or y = 1
sub back into the substitution and you have two quadratic equations to solve.
e.g
√(x^2 + x) = -2 which of course cannot have a real number solution and
√(x^2+x) = 1
square both sides and proceed from there.
Answered by
Anonymous
A line passes through the points whose coordinates are (c,3c) and (2c,5c).Assuming that c is not 0 find the slope of the line
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