Question

Find the area of a trapezoid that has one base length measuring 18 mm, one base measuring 16 mm, and a height of 9 mm.(1 point)
mm2

Answer 1

To find the area of a trapezoid, you can use the formula:

\[
\text{Area} = \frac{1}{2} \times (b_1 + b_2) \times h
\]

where \( b_1 \) and \( b_2 \) are the lengths of the two bases, and \( h \) is the height.

In this case:
- \( b_1 = 18 \) mm
- \( b_2 = 16 \) mm
- \( h = 9 \) mm

Now, substituting the values into the formula:

\[
\text{Area} = \frac{1}{2} \times (18 + 16) \times 9
\]
\[
= \frac{1}{2} \times 34 \times 9
\]
\[
= 17 \times 9
\]
\[
= 153 \, \text{mm}^2
\]

Therefore, the area of the trapezoid is **153 mm²**.