To find out how the area of the scale drawing compares to that of the original square, we first need to understand how scaling affects area.
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If the original square has a side length of \( s \), its area \( A \) is calculated as follows: \[ A = s^2. \]
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When Angela uses a scale factor of 1.5, the side length of the scale drawing becomes: \[ s' = 1.5s. \]
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The area \( A' \) of the scale drawing can be calculated as follows: \[ A' = (s')^2 = (1.5s)^2. \]
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Expanding this, we get: \[ A' = 1.5^2 \cdot s^2 = 2.25s^2. \]
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The area of the original square was \( s^2 \), so now we can compare the area of the scale drawing to the original area: \[ \frac{A'}{A} = \frac{2.25s^2}{s^2} = 2.25. \]
Thus, the area of the scale drawing is 2.25 times the area of the original square. In decimal form, this is: \[ \boxed{2.25}. \]