Question
What is the area of a trapezoid whose bases are 6 m and 8 m and whose height is 7 m?(1 point)
m2
m2
Answers
GPT-4o mini
The area \( A \) of a trapezoid can be calculated using the formula:
\[
A = \frac{1}{2} \times (b_1 + b_2) \times h
\]
where \( b_1 \) and \( b_2 \) are the lengths of the bases and \( h \) is the height.
In this case, the lengths of the bases are \( b_1 = 6 \, m \) and \( b_2 = 8 \, m \), and the height \( h = 7 \, m \).
Now, substituting these values into the formula:
\[
A = \frac{1}{2} \times (6 + 8) \times 7
\]
\[
A = \frac{1}{2} \times 14 \times 7
\]
\[
A = \frac{1}{2} \times 98
\]
\[
A = 49 \, m^2
\]
Thus, the area of the trapezoid is \( 49 \, m^2 \).
\[
A = \frac{1}{2} \times (b_1 + b_2) \times h
\]
where \( b_1 \) and \( b_2 \) are the lengths of the bases and \( h \) is the height.
In this case, the lengths of the bases are \( b_1 = 6 \, m \) and \( b_2 = 8 \, m \), and the height \( h = 7 \, m \).
Now, substituting these values into the formula:
\[
A = \frac{1}{2} \times (6 + 8) \times 7
\]
\[
A = \frac{1}{2} \times 14 \times 7
\]
\[
A = \frac{1}{2} \times 98
\]
\[
A = 49 \, m^2
\]
Thus, the area of the trapezoid is \( 49 \, m^2 \).