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A horizontally aligned rectangle is shown as 10 meters long and 6 meters wide. A rectangular area is removed from the bottom right corner, with the remaining length as 8 meters and remaining width as 4 meters. Right angle marks are shown in the five corners of the composite shape.

Rebekah designs a playing field for a new sport. The playing field is pictured. What is the area of the playing field?

(1 point)
Responses

60 square meters
60 square meters

32 square meters
32 square meters

58 square meters
58 square meters

56 square meters
56 square meters

1 answer

To find the area of the playing field, we can start with the area of the original rectangle and then subtract the area of the removed rectangle.

  1. Calculate the area of the original rectangle:

    • Length = 10 meters
    • Width = 6 meters
    • Area = Length × Width = 10 × 6 = 60 square meters

  2. Calculate the area of the removed rectangle:

    • Remaining Length = 8 meters
    • Remaining Width = 4 meters
    • Area of the remaining rectangle = 8 × 4 = 32 square meters

  3. The area of the removed rectangle (not directly given but inferred) can also be calculated:

    • Original Area - Remaining Area = 60 square meters - 32 square meters = 28 square meters.

  4. Now, we want to find the area of the playing field, which is the original area minus the area of the removed part:

    • Area of the playing field = Area of the original rectangle - Area of the removed rectangle
    • Since the remaining area is already given as part of the remaining rectangle, the subtraction shows that there's some confusion in the position of cutting.

When we compare this to the options provided, the area of the playing field ultimately leads back to the area that remains:

  • Remaining Rectangle Area = 8 m × 4 m = 32 m²

Therefore, it should be straightforward from asking about the total area left, assuming a mix was running regarding what's being kept or what's being removed:

Final area calculated is 32 square meters.

Thus, the answer is: 32 square meters.