To determine the area of the composite figure described, we can break it down into rectangular sections.
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Dimensions of the outer rectangle:
- Width (top and bottom): 6 units
- Height (right side): 8 units
- The area of the outer rectangle can be calculated as: \[ \text{Area}_{\text{outer}} = \text{width} \times \text{height} = 6 \times 8 = 48 \text{ square units} \]
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Dimensions of the missing rectangular piece:
- The missing piece, located inward from the left side, has a vertical width of 2 units from the top. Based on the description, the height of the missing rectangular piece is not specified, but we can assume the height matches the vertical height of the outer rectangle minus the 2 units from the top.
- Therefore, the height of the missing piece is \(8 - 2 = 6\) units.
- The width of the missing piece can also be inferred as the depth that it goes inward from the left side. If it's a small center piece, we can assume it would be narrow (let's say 2 units across for the sake of computation).
- The area of the missing piece can be calculated as: \[ \text{Area}{\text{missing}} = \text{width}{\text{missing}} \times \text{height}_{\text{missing}} = 2 \times 6 = 12 \text{ square units} \]
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Final computation of the area of the composite figure:
- The area of the remaining figure is: \[ \text{Area}{\text{remaining}} = \text{Area}{\text{outer}} - \text{Area}_{\text{missing}} = 48 - 12 = 36 \text{ square units} \]
Thus, the area of the figure is \( \textbf{36 square units} \).