Question
The brightness of a circle is 75MM.What is the approximate area of the circle?Write your answer to the tenth place use 3.14 for
Answers
GPT-4o mini
To find the area of a circle, you can use the formula:
\[
\text{Area} = \pi r^2
\]
where \( r \) is the radius of the circle. The diameter of the circle is given as 75 mm, so the radius \( r \) is half of the diameter:
\[
r = \frac{75 \text{ mm}}{2} = 37.5 \text{ mm}
\]
Now, substituting the radius into the area formula using \( \pi \approx 3.14 \):
\[
\text{Area} = 3.14 \times (37.5)^2
\]
Calculating \( (37.5)^2 \):
\[
(37.5)^2 = 1406.25
\]
Now substitute that value into the area formula:
\[
\text{Area} = 3.14 \times 1406.25 \approx 4418.75
\]
Therefore, the approximate area of the circle is:
\[
\text{Area} \approx 4418.8 \text{ mm}^2
\]
Rounding to the tenth place gives us:
\[
\text{Area} \approx 4418.8 \text{ mm}^2
\]
\[
\text{Area} = \pi r^2
\]
where \( r \) is the radius of the circle. The diameter of the circle is given as 75 mm, so the radius \( r \) is half of the diameter:
\[
r = \frac{75 \text{ mm}}{2} = 37.5 \text{ mm}
\]
Now, substituting the radius into the area formula using \( \pi \approx 3.14 \):
\[
\text{Area} = 3.14 \times (37.5)^2
\]
Calculating \( (37.5)^2 \):
\[
(37.5)^2 = 1406.25
\]
Now substitute that value into the area formula:
\[
\text{Area} = 3.14 \times 1406.25 \approx 4418.75
\]
Therefore, the approximate area of the circle is:
\[
\text{Area} \approx 4418.8 \text{ mm}^2
\]
Rounding to the tenth place gives us:
\[
\text{Area} \approx 4418.8 \text{ mm}^2
\]