To determine whether the point (3, 8) is a solution to the inequalities \( y > x + 5 \) and \( y \leq 6x - 3 \), we need to evaluate both inequalities.
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Evaluate the first inequality: \[ y > x + 5 \] Substitute \( x = 3 \) and \( y = 8 \): \[ 8 > 3 + 5 \] \[ 8 > 8 \] This is false since 8 is not greater than 8.
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Evaluate the second inequality: \[ y \leq 6x - 3 \] Substitute \( x = 3 \) and \( y = 8 \): \[ 8 \leq 6(3) - 3 \] \[ 8 \leq 18 - 3 \] \[ 8 \leq 15 \] This is true.
The point (3, 8) is not in the solution set for \( y > x + 5 \) but it is in the solution set for \( y \leq 6x - 3 \).
Thus, the correct response is: no, it is in the solution set for \( y \leq 6x - 3 \), but on the line for \( y > x + 5 \).