Asked by trigofunctions
the L and C State building is 1,250 m tall. What is the angle of elevation of the top from a point on the ground 1,760 m from the base of the building?
Answers
Answered by
Tony
Let the angle of elevation of the top of the building from a point 1,760 m from the base of the building be P degree.
Then, tan P = 1250/1760 = 0.71 tan 36 degrees
Hence, the angle of elevation is 36 degrees.
Then, tan P = 1250/1760 = 0.71 tan 36 degrees
Hence, the angle of elevation is 36 degrees.
Answered by
Tony
Let the angle of elevation of the top of the building from a point 1,760 m from the base of the building be P degree.
Then, tan P = 1250/1760 = 0.71 = tan 36 degrees
Hence, the angle of elevation is 36 degrees.
Then, tan P = 1250/1760 = 0.71 = tan 36 degrees
Hence, the angle of elevation is 36 degrees.
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