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Sue is wrapping books to give as gifts. Book A has a length of 6.5 inches, a width of 1 inch, and a height of 8.5 inches. Book...Asked by The Skibidi Rizzler
Sue is wrapping books to give as gifts. Book A has a
length of 6.5 inches, a width of 1 inch, and a height of
8.5 inches. Book B has a length of 5.5 inches, a width of
2 inches, and a height of 8 inches. Based on surface
area, which book will require less wrapping paper?
(1 point)
Book B will require less wrapping paper because its
surface area is less than the surface area of
Book A.
1.5 in.
2
Book B will require less wrapping paper because its
surface area is less than the surface area of
Book A.
0.5 in.
2
Book A will require less wrapping paper because its
surface area is less than the surface area
of Book B.
32.75 in.
2
Book A will require less wrapping paper because its
surface area is less than the surface area of
Book B.
1.5 in.
2
length of 6.5 inches, a width of 1 inch, and a height of
8.5 inches. Book B has a length of 5.5 inches, a width of
2 inches, and a height of 8 inches. Based on surface
area, which book will require less wrapping paper?
(1 point)
Book B will require less wrapping paper because its
surface area is less than the surface area of
Book A.
1.5 in.
2
Book B will require less wrapping paper because its
surface area is less than the surface area of
Book A.
0.5 in.
2
Book A will require less wrapping paper because its
surface area is less than the surface area
of Book B.
32.75 in.
2
Book A will require less wrapping paper because its
surface area is less than the surface area of
Book B.
1.5 in.
2
Answers
Answered by
The Skibidi Rizzler
whats the inches
Answered by
GPT-4o mini
To determine which book requires less wrapping paper based on surface area, we need to calculate the surface area for both Book A and Book B using the formula for the surface area of a rectangular prism:
\[
\text{Surface Area} = 2(lw + lh + wh)
\]
where \( l \) is the length, \( w \) is the width, and \( h \) is the height.
### For Book A:
- Length \( l = 6.5 \) inches
- Width \( w = 1 \) inch
- Height \( h = 8.5 \) inches
Calculating the surface area:
\[
\text{Surface Area}_A = 2(lw + lh + wh)
\]
Calculating each component:
- \( lw = 6.5 \times 1 = 6.5 \)
- \( lh = 6.5 \times 8.5 = 55.25 \)
- \( wh = 1 \times 8.5 = 8.5 \)
Now, summing them up:
\[
lw + lh + wh = 6.5 + 55.25 + 8.5 = 70.25
\]
Now, calculating the total surface area:
\[
\text{Surface Area}_A = 2 \times 70.25 = 140.5 \, \text{in}^2
\]
### For Book B:
- Length \( l = 5.5 \) inches
- Width \( w = 2 \) inches
- Height \( h = 8 \) inches
Calculating the surface area:
\[
\text{Surface Area}_B = 2(lw + lh + wh)
\]
Calculating each component:
- \( lw = 5.5 \times 2 = 11 \)
- \( lh = 5.5 \times 8 = 44 \)
- \( wh = 2 \times 8 = 16 \)
Now, summing them up:
\[
lw + lh + wh = 11 + 44 + 16 = 71
\]
Now, calculating the total surface area:
\[
\text{Surface Area}_B = 2 \times 71 = 142 \, \text{in}^2
\]
### Conclusion:
- Surface Area of Book A: 140.5 in²
- Surface Area of Book B: 142 in²
Book A requires less wrapping paper because its surface area is less than the surface area of Book B.
The correct option is: **Book A will require less wrapping paper because its surface area is less than the surface area of Book B.**
\[
\text{Surface Area} = 2(lw + lh + wh)
\]
where \( l \) is the length, \( w \) is the width, and \( h \) is the height.
### For Book A:
- Length \( l = 6.5 \) inches
- Width \( w = 1 \) inch
- Height \( h = 8.5 \) inches
Calculating the surface area:
\[
\text{Surface Area}_A = 2(lw + lh + wh)
\]
Calculating each component:
- \( lw = 6.5 \times 1 = 6.5 \)
- \( lh = 6.5 \times 8.5 = 55.25 \)
- \( wh = 1 \times 8.5 = 8.5 \)
Now, summing them up:
\[
lw + lh + wh = 6.5 + 55.25 + 8.5 = 70.25
\]
Now, calculating the total surface area:
\[
\text{Surface Area}_A = 2 \times 70.25 = 140.5 \, \text{in}^2
\]
### For Book B:
- Length \( l = 5.5 \) inches
- Width \( w = 2 \) inches
- Height \( h = 8 \) inches
Calculating the surface area:
\[
\text{Surface Area}_B = 2(lw + lh + wh)
\]
Calculating each component:
- \( lw = 5.5 \times 2 = 11 \)
- \( lh = 5.5 \times 8 = 44 \)
- \( wh = 2 \times 8 = 16 \)
Now, summing them up:
\[
lw + lh + wh = 11 + 44 + 16 = 71
\]
Now, calculating the total surface area:
\[
\text{Surface Area}_B = 2 \times 71 = 142 \, \text{in}^2
\]
### Conclusion:
- Surface Area of Book A: 140.5 in²
- Surface Area of Book B: 142 in²
Book A requires less wrapping paper because its surface area is less than the surface area of Book B.
The correct option is: **Book A will require less wrapping paper because its surface area is less than the surface area of Book B.**
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