Question
This table shows the relationship between x and y values that will contribute to linear functions.
x
y
4 38
6 58
Write the equation of the linear function that models the relationship shown in the table.
(1 point)
Responses
y=−10x+78
y equals negative 10 x plus 78
y=10x−2
y equals 10 x minus 2
y=10x+2
y equals 10 x plus 2
y=x+34
x
y
4 38
6 58
Write the equation of the linear function that models the relationship shown in the table.
(1 point)
Responses
y=−10x+78
y equals negative 10 x plus 78
y=10x−2
y equals 10 x minus 2
y=10x+2
y equals 10 x plus 2
y=x+34
Answers
GPT-4o mini
To find the equation of the linear function that models the relationship given in the table, we can first determine the slope (m) using the two points: (4, 38) and (6, 58).
The formula for the slope between two points \((x_1, y_1)\) and \((x_2, y_2)\) is:
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
Let's assign:
- \( (x_1, y_1) = (4, 38) \)
- \( (x_2, y_2) = (6, 58) \)
Now calculate the slope:
\[
m = \frac{58 - 38}{6 - 4} = \frac{20}{2} = 10
\]
Now that we have the slope \(m = 10\), we can use the point-slope form of the linear equation, which is:
\[
y - y_1 = m(x - x_1)
\]
Using point \((4, 38)\):
\[
y - 38 = 10(x - 4)
\]
Distribute the slope:
\[
y - 38 = 10x - 40
\]
Add 38 to both sides:
\[
y = 10x - 2
\]
Thus, the equation of the linear function that models the relationship shown in the table is:
\[
\boxed{y = 10x - 2}
\]
The formula for the slope between two points \((x_1, y_1)\) and \((x_2, y_2)\) is:
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
Let's assign:
- \( (x_1, y_1) = (4, 38) \)
- \( (x_2, y_2) = (6, 58) \)
Now calculate the slope:
\[
m = \frac{58 - 38}{6 - 4} = \frac{20}{2} = 10
\]
Now that we have the slope \(m = 10\), we can use the point-slope form of the linear equation, which is:
\[
y - y_1 = m(x - x_1)
\]
Using point \((4, 38)\):
\[
y - 38 = 10(x - 4)
\]
Distribute the slope:
\[
y - 38 = 10x - 40
\]
Add 38 to both sides:
\[
y = 10x - 2
\]
Thus, the equation of the linear function that models the relationship shown in the table is:
\[
\boxed{y = 10x - 2}
\]