Asked by leanne
solve 1-tan^2x=0 , 0≤x≤2pi
Answers
Answered by
Reiny
1-tan^2x=0
tan^2 x = 1
tan x = ±1
x = π/4, π - π/4, π + π/4, or 2π - π/4
x π/4, 3π/4, 5π/4, 7π/4
tan^2 x = 1
tan x = ±1
x = π/4, π - π/4, π + π/4, or 2π - π/4
x π/4, 3π/4, 5π/4, 7π/4
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