Asked by amy
Hi. I have an answer for this question however, not sure. In a certain lottery, 4 numbers between 1 and 10 inclusive are drawn. These are the winning numbers. How many different selections are possible? Assume that the order in which the numbers are drawn are not imprt. (10*9*8*7)/(1*2*3*4)=210.4! = 4*3*2*1= with 24 as the final answer??
Answers
Answered by
Reiny
You are choosing 4 from 10 or C(10,4) = 210
(why are you multiplying 210 by 4! ?
then the order would be important. )
(why are you multiplying 210 by 4! ?
then the order would be important. )
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