To solve for the angles \( m\angle I \) and \( m\angle U \) in the cyclic quadrilateral AEIU inscribed in circle O, we can use the properties of inscribed angles.
Given:
- \( m\angle A = 27^\circ \)
- \( m\angle E = 2(m\angle A) = 2(27^\circ) = 54^\circ \)
In a cyclic quadrilateral, the opposite angles are supplementary, which means that: \[ m\angle A + m\angle I = 180^\circ \] \[ m\angle E + m\angle U = 180^\circ \]
Now we can substitute the values we know into these equations:
-
For angle \( I \): \[ m\angle I = 180^\circ - m\angle A = 180^\circ - 27^\circ = 153^\circ \]
-
For angle \( U \): \[ m\angle U = 180^\circ - m\angle E = 180^\circ - 54^\circ = 126^\circ \]
Thus, we find:
- \( m\angle I = 153^\circ \)
- \( m\angle U = 126^\circ \)
Therefore, the correct response is: m∠I=153° and m∠U=126°.