Which of the following equations has the solution set {−3}

Question

?(1 point)
Responses

4x−8=4
4 x minus 8 equals 4

4x−8=−4
4 x minus 8 equals negative 4

4x+8=−4
4 x plus 8 equals negative 4

4x+8=4

Answer 1

To determine which of the given equations has the solution set \({-3}\), we can substitute \(-3\) into each equation and check if it holds true.

1. Equation: \(4x - 8 = 4\)
   Substitute \(x = -3\): \[ 4(-3) - 8 = -12 - 8 = -20 \quad (\text{not } 4) \]

2. Equation: \(4x - 8 = -4\)
   Substitute \(x = -3\): \[ 4(-3) - 8 = -12 - 8 = -20 \quad (\text{not } -4) \]

3. Equation: \(4x + 8 = -4\)
   Substitute \(x = -3\): \[ 4(-3) + 8 = -12 + 8 = -4 \quad (\text{is } -4) \] This equation is true.

4. Equation: \(4x + 8 = 4\)
   Substitute \(x = -3\): \[ 4(-3) + 8 = -12 + 8 = -4 \quad (\text{not } 4) \]

From the evaluations, the only equation that holds true when \(x = -3\) is:

\(4x + 8 = -4\).

Thus, the answer is: \(4x + 8 = -4\).