Asked by Jaz
Which of the following is a factor of 2 x squared minus x minus 6 equals 0?
(1 point)
Responses
x minus 3
Image with alt text: x minus 3
x + 2
x + 2
2x + 3
2 x + 3
(1 point)
Responses
x minus 3
Image with alt text: x minus 3
x + 2
x + 2
2x + 3
2 x + 3
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To determine which of the given options is a factor of the quadratic equation \( 2x^2 - x - 6 = 0 \), we can factor the quadratic expression.
We are looking for two numbers that multiply to \( 2 \times (-6) = -12 \) and add to \( -1 \) (the coefficient of the middle term, \( -x \)).
The numbers that meet these criteria are \( -4 \) and \( 3 \).
Now, we can rewrite the middle term:
\[
2x^2 - 4x + 3x - 6 = 0
\]
Next, we factor by grouping:
\[
(2x^2 - 4x) + (3x - 6) = 0
\]
This simplifies to:
\[
2x(x - 2) + 3(x - 2) = 0
\]
Now, we can factor out the common term \( (x - 2) \):
\[
(2x + 3)(x - 2) = 0
\]
Therefore, the factors of the quadratic are \( (2x + 3) \) and \( (x - 2) \).
Now we can check the options:
1. \( x - 3 \) (not a factor)
2. \( x + 2 \) (not a factor)
3. \( 2x + 3 \) (is a factor)
Thus, the correct response is:
**2x + 3**
We are looking for two numbers that multiply to \( 2 \times (-6) = -12 \) and add to \( -1 \) (the coefficient of the middle term, \( -x \)).
The numbers that meet these criteria are \( -4 \) and \( 3 \).
Now, we can rewrite the middle term:
\[
2x^2 - 4x + 3x - 6 = 0
\]
Next, we factor by grouping:
\[
(2x^2 - 4x) + (3x - 6) = 0
\]
This simplifies to:
\[
2x(x - 2) + 3(x - 2) = 0
\]
Now, we can factor out the common term \( (x - 2) \):
\[
(2x + 3)(x - 2) = 0
\]
Therefore, the factors of the quadratic are \( (2x + 3) \) and \( (x - 2) \).
Now we can check the options:
1. \( x - 3 \) (not a factor)
2. \( x + 2 \) (not a factor)
3. \( 2x + 3 \) (is a factor)
Thus, the correct response is:
**2x + 3**
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