To determine which of the given options is a factor of the quadratic equation \( 2x^2 - x - 6 = 0 \), we can factor the quadratic expression.
We are looking for two numbers that multiply to \( 2 \times (-6) = -12 \) and add to \( -1 \) (the coefficient of the middle term, \( -x \)).
The numbers that meet these criteria are \( -4 \) and \( 3 \).
Now, we can rewrite the middle term:
\[ 2x^2 - 4x + 3x - 6 = 0 \]
Next, we factor by grouping:
\[ (2x^2 - 4x) + (3x - 6) = 0 \]
This simplifies to:
\[ 2x(x - 2) + 3(x - 2) = 0 \]
Now, we can factor out the common term \( (x - 2) \):
\[ (2x + 3)(x - 2) = 0 \]
Therefore, the factors of the quadratic are \( (2x + 3) \) and \( (x - 2) \).
Now we can check the options:
- \( x - 3 \) (not a factor)
- \( x + 2 \) (not a factor)
- \( 2x + 3 \) (is a factor)
Thus, the correct response is:
2x + 3