Given the interval \(\frac{\pi}{2} \leq x \leq \pi\), we can analyze the signs of the trigonometric functions:
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\(\cos x\): The cosine function is negative in the second quadrant. Therefore, \(\cos x < 0\).
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\(\sin x\): The sine function is positive in the second quadrant. Therefore, \(\sin x > 0\).
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\(\tan x\): The tangent function is defined as \(\tan x = \frac{\sin x}{\cos x}\). Since \(\sin x\) is positive and \(\cos x\) is negative, \(\tan x < 0\).
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\(\sec x\): The secant function is the reciprocal of cosine, \(\sec x = \frac{1}{\cos x}\). Since \(\cos x < 0\), \(\sec x < 0\).
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\(\csc x\): The cosecant function is the reciprocal of sine, \(\csc x = \frac{1}{\sin x}\). Since \(\sin x > 0\), \(\csc x > 0\).
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\(\cot x\): The cotangent function is defined as \(\cot x = \frac{\cos x}{\sin x}\). Since \(\cos x < 0\) and \(\sin x > 0\), \(\cot x < 0\).
In summary:
- \(\cos x < 0\)
- \(\sin x > 0\)
- \(\tan x < 0\)
- \(\sec x < 0\)
- \(\csc x > 0\)
- \(\cot x < 0\)
Thus, the functions that are positive in the interval \(\frac{\pi}{2} \leq x \leq \pi\) are:
- \(\sin x\)
- \(\csc x\)
So the correct responses are:
- \(\sin x\)
- \(\csc x\)