Asked by Jaz
Question
A telephone pole that is 14 ft. tall has fallen against a house. If the top of the telephone pole touches the house 8 ft. above the ground, what is the angle that the telephone pole makes with the ground?
(1 point)
Responses
29.7°
29.7°
55.2°
55.2°
60.3°
60.3°
34.8°
34.8°
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A telephone pole that is 14 ft. tall has fallen against a house. If the top of the telephone pole touches the house 8 ft. above the ground, what is the angle that the telephone pole makes with the ground?
(1 point)
Responses
29.7°
29.7°
55.2°
55.2°
60.3°
60.3°
34.8°
34.8°
Skip to navigation
Answers
Answered by
GPT-4o mini
To find the angle that the fallen telephone pole makes with the ground, we can use some basic trigonometry. We'll visualize this scenario and identify a right triangle formed by the following:
- The height at which the top of the telephone pole touches the house (8 ft) represents one side (opposite) of the triangle.
- The height of the telephone pole (14 ft) represents the length of the pole (hypotenuse).
- The angle θ is the angle between the ground and the telephone pole.
We can use the sine function, which relates the opposite side to the hypotenuse:
\[
\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}
\]
Here:
- Opposite = 8 ft
- Hypotenuse = 14 ft
Plugging in the values:
\[
\sin(\theta) = \frac{8}{14} = \frac{4}{7}
\]
Now, we can find θ by taking the inverse sine (arcsin) of \(\frac{4}{7}\):
\[
\theta = \arcsin\left(\frac{4}{7}\right)
\]
Using a calculator to find the angle:
\[
\theta \approx 29.7°
\]
Thus, the angle that the telephone pole makes with the ground is approximately **29.7°**.
So the answer is:
**29.7°**
- The height at which the top of the telephone pole touches the house (8 ft) represents one side (opposite) of the triangle.
- The height of the telephone pole (14 ft) represents the length of the pole (hypotenuse).
- The angle θ is the angle between the ground and the telephone pole.
We can use the sine function, which relates the opposite side to the hypotenuse:
\[
\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}
\]
Here:
- Opposite = 8 ft
- Hypotenuse = 14 ft
Plugging in the values:
\[
\sin(\theta) = \frac{8}{14} = \frac{4}{7}
\]
Now, we can find θ by taking the inverse sine (arcsin) of \(\frac{4}{7}\):
\[
\theta = \arcsin\left(\frac{4}{7}\right)
\]
Using a calculator to find the angle:
\[
\theta \approx 29.7°
\]
Thus, the angle that the telephone pole makes with the ground is approximately **29.7°**.
So the answer is:
**29.7°**
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