Question

There are 13 elements in a data set. The 13 elements in a second data set are obtained by increasing each element in the first set by 5. The 13 elements in a third set are obtained by multiplying each element in a second data set by 3. The median of the third set 42. What is the median of the first data set?

Answer 1

Let the elements of the first data set be denoted as \( x_1, x_2, \ldots, x_{13} \).

1. In the second data set, each element is increased by 5:
\[
y_i = x_i + 5 \quad \text{for } i = 1, 2, \ldots, 13.
\]
Thus, the elements of the second data set are \( y_1, y_2, \ldots, y_{13} \).

2. In the third data set, each element of the second data set is multiplied by 3:
\[
z_i = 3y_i = 3(x_i + 5) = 3x_i + 15 \quad \text{for } i = 1, 2, \ldots, 13.
\]
Thus, the elements of the third data set are \( z_1, z_2, \ldots, z_{13} \).

3. We know the median of the third set is 42. Since there are 13 elements in this data set, the median is the 7th element when the elements are ordered:
\[
z_7 = 42.
\]

4. From the expression for \( z_i \):
\[
z_7 = 3x_7 + 15.
\]
Setting this equal to 42 gives:
\[
3x_7 + 15 = 42.
\]

5. To solve for \( x_7 \):
\[
3x_7 = 42 - 15,
\]
\[
3x_7 = 27,
\]
\[
x_7 = \frac{27}{3} = 9.
\]

6. The median of the first data set is therefore:
\[
\boxed{9}.
\]