whats the area and perimeter of 56.3 time 53 times 95

1 answer

To find the area and perimeter, we first need to clarify whether you're asking for the area and perimeter of a rectangle with the given dimensions or if you're asking for some other mathematical operation involving those numbers.

Assuming you're referring to the dimensions of a rectangle with length 56.3 and width 53:

Area of the rectangle: \[ \text{Area} = \text{length} \times \text{width} = 56.3 \times 53 = 2983.9 \]

Perimeter of the rectangle: \[ \text{Perimeter} = 2 \times (\text{length} + \text{width}) = 2 \times (56.3 + 53) = 2 \times 109.3 = 218.6 \]

If you meant to include the third dimension multiplied by 95 in a different context, please provide more details about how you would like to calculate it! However, based on the provided values, the area is 2983.9 and the perimeter is 218.6.