Question

solve the area and perimeter of 8 times 29 times 16 times 22

Answer 1

To calculate the area and perimeter given the dimensions, we first need to clarify what shape we are dealing with. However, based on your request, it seems you want to find the area and perimeter of a rectangle defined by the pairs of dimensions.

Let's assume you have a rectangle with dimensions 8 and 29 for one pair, and 16 and 22 for the other. This means we have a rectangle with:

**Length (L) = 29 (from the first pair)**
**Width (W) = 8 (from the first pair)**

### Area
The area \( A \) of a rectangle is given by:

\[
A = L \times W
\]

So, for the first pair:

\[
A = 29 \times 8 = 232
\]

### Perimeter
The perimeter \( P \) of a rectangle is given by:

\[
P = 2 \times (L + W)
\]

Thus,

\[
P = 2 \times (29 + 8) = 2 \times 37 = 74
\]

If you intended to use the second pair of numbers (16 and 22), we would do the same calculation:

**Length (L) = 22**
**Width (W) = 16**

### Area
\[
A = 22 \times 16 = 352
\]

### Perimeter
\[
P = 2 \times (22 + 16) = 2 \times 38 = 76
\]

So, the area and perimeter for the dimensions 8 and 29 are **Area: 232**, **Perimeter: 74**, and for the dimensions 16 and 22 are **Area: 352**, **Perimeter: 76**. Please clarify if you meant something different!