Write prime factors of 36

1 answer

The prime factorization of 36 can be determined by dividing it by the smallest prime numbers.

  1. Start with 36 and divide by 2 (the smallest prime number):
    • \(36 \div 2 = 18\)
  2. Divide 18 by 2 again:
    • \(18 \div 2 = 9\)
  3. Now, divide 9 by 3 (the next smallest prime):
    • \(9 \div 3 = 3\)
  4. Finally, divide 3 by itself:
    • \(3 \div 3 = 1\)

Thus, you can express 36 as: \[ 36 = 2^2 \times 3^2 \]

The prime factors of 36 are therefore 2 and 3.