Asked by Roxie
how many grams of CaO are required for complete reaction with the HCl in 275mL of a 0.523 M HCl?
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Answered by
Writeacher
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Answered by
bobpursley
write the balanced equation:
CaO + 2HCl >> CaCl2 + H2O
Note then that it takes half as many moles of CaO as it does HCl.
Moles HCl: .275*.523
moles CaO: half that.
grams CaO: molesCaO*molmassCaO
CaO + 2HCl >> CaCl2 + H2O
Note then that it takes half as many moles of CaO as it does HCl.
Moles HCl: .275*.523
moles CaO: half that.
grams CaO: molesCaO*molmassCaO
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