Question

What is the frequency of violet light with the wave length of 408nm

Answer 1

To find the frequency of violet light with a wavelength of 408 nm (nanometers), you can use the speed of light equation:

\[
c = \lambda \cdot f
\]

where:
- \( c \) is the speed of light (\( 3.00 \times 10^8 \) meters per second),
- \( \lambda \) is the wavelength (in meters),
- \( f \) is the frequency (in hertz).

First, convert the wavelength from nanometers to meters:

\[
\lambda = 408 \, \text{nm} = 408 \times 10^{-9} \, \text{m}
\]

Now, rearranging the formula to solve for frequency \( f \):

\[
f = \frac{c}{\lambda}
\]

Substituting the values:

\[
f = \frac{3.00 \times 10^8 \, \text{m/s}}{408 \times 10^{-9} \, \text{m}}
\]

Now, calculate \( f \):

\[
f \approx \frac{3.00 \times 10^8}{408 \times 10^{-9}} \approx 7.35 \times 10^{14} \, \text{Hz}
\]

Therefore, the frequency of violet light with a wavelength of 408 nm is approximately \( 7.35 \times 10^{14} \) hertz.