What is the area of the sector of a circle with θ=122°

and a diameter of 18 inches? Write your answer to two decimal places.(1 point)
A=
π in.2

1 answer

To find the area of a sector of a circle, we can use the formula:

\[ A = \frac{\theta}{360^\circ} \times \pi r^2 \]

where \( A \) is the area of the sector, \( \theta \) is the angle in degrees, and \( r \) is the radius of the circle.

First, we need to determine the radius of the circle. The diameter is given as 18 inches, so the radius \( r \) is:

\[ r = \frac{diameter}{2} = \frac{18}{2} = 9 \text{ inches} \]

Now, we can substitute the values into the formula. The angle \( \theta \) is 122°, and the radius \( r \) is 9 inches:

\[ A = \frac{122}{360} \times \pi (9^2) \]

Calculating \( 9^2 \):

\[ 9^2 = 81 \]

Now plugging this in:

\[ A = \frac{122}{360} \times \pi \times 81 \]

Calculating \( \frac{122}{360} \):

\[ \frac{122}{360} \approx 0.338888 \]

Now we calculate the area:

\[ A \approx 0.338888 \times \pi \times 81 \]

Calculating \( 81 \times 0.338888 \):

\[ 81 \times 0.338888 \approx 27.5 \]

Now, substituting this back in for the area:

\[ A \approx 27.5\pi \]

Now, we need to express it in terms of \(\pi\) and convert it to a decimal for the final answer.

Calculating \( 27.5\pi \):

\[ A \approx 27.5 \times 3.14159 \approx 86.493 \]

Rounding to two decimal places, we have:

\[ A \approx 86.49 \]

So, the area of the sector is:

\[ A = 27.5\pi \text{ in}^2 \quad (or \approx 86.49 \text{ in}^2) \]

In \(\pi\) form, the answer is:

\[ A = 27.5\pi \text{ in}^2 \]

In approximate numerical form to two decimal places:

\[ A \approx 86.49 \text{ in}^2 \]