Asked by Shaila

A 1000kg load is suspended from the end of a horizontal boom. The boom is supported by a cable that makes an angle of 35deg with the boom.

a) what is the tension in the cable?
b) what is the horizontal force on the boom?

Answers

Answered by Damon
1000*9.8 = 9800 Newtons weight
Force up from cable = T sin 35
force up from cable = weight down
T sin 35 = 9800
Answered by Damon
Force inward from tension = T cos 35
= 9800 cos 35/sin 35
which is the horizontal compression force on the boom.
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions