Asked by Ellen

what is the pH of 0.15 M NaF?
Answered by DrBob222
F^- + HOH ==> HF + OH^-

Kb = (Kw/Ka) = (HF)(OH^-)/(F^-)
Set up an ICE chart, substitute into the Kb expression and solve for OH, convert to pOH, then to pH.
There are no AI answers yet. The ability to request AI answers is coming soon!