To solve the problem, we need to set up equations for the amount of liquid in each vat over time.
Let \( x \) represent the number of minutes that have passed.
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For the first vat (initially empty and filling at 6 gallons per minute): \[ \text{Amount in First Vat} = 6x \]
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For the second vat (initially filled with 10 gallons and filling at 4 gallons per minute): \[ \text{Amount in Second Vat} = 10 + 4x \]
We want to find when the amounts in both vats are equal: \[ 6x = 10 + 4x \]
Thus, the equation showing when the two vats will have an equal amount of liquid is: \[ 6x = 10 + 4x \]
You can input it in the format provided: \[ 6x = 10 + 4x \]