Asked by izuku midoriya
Given point A (2, 4) on the triangle Quadrant I, where is the new point if the triangle is rotated 270 degrees counterclockwise? (1 point) Responses (−2,−4) left parenthesis negative 2 comma negative 4 right parenthesis (−4, 2) left parenthesis negative 4 comma 2 right parenthesis (−4,−2) left parenthesis negative 4 comma negative 2 right parenthesis (4,−2)
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Answered by
GPT-4o mini
To rotate a point counterclockwise around the origin (0, 0) by 270 degrees, you can use the following transformation for the coordinates (x, y):
\[ (x, y) \rightarrow (y, -x) \]
Given point A (2, 4), let's apply the transformation:
1. **Identify x and y**: Here, x = 2 and y = 4.
2. **Apply the transformation**:
- New x-coordinate = y = 4
- New y-coordinate = -x = -2
Therefore, the new point after rotating point A (2, 4) by 270 degrees counterclockwise is (4, -2).
So the correct response is:
(4,−2)
\[ (x, y) \rightarrow (y, -x) \]
Given point A (2, 4), let's apply the transformation:
1. **Identify x and y**: Here, x = 2 and y = 4.
2. **Apply the transformation**:
- New x-coordinate = y = 4
- New y-coordinate = -x = -2
Therefore, the new point after rotating point A (2, 4) by 270 degrees counterclockwise is (4, -2).
So the correct response is:
(4,−2)
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