Asked by Anonymous
How many moles of water will produced at equilibrium be if there is 1.0 mole of carbon dioxide formed at equilibrium?
2 C2 H6(g) + 7 O2(g) <==> 4 CO2(g) + 6 H2 O(g)
...
[CO2]^4[H20]^6/[C2 H6]^2[O2]^7
2 C2 H6(g) + 7 O2(g) <==> 4 CO2(g) + 6 H2 O(g)
...
[CO2]^4[H20]^6/[C2 H6]^2[O2]^7
Answers
Answered by
DrBob222
You are making it way too complicated.
1 mole CO2 x (6 moles H2O/4 moles CO) = ??moles H2O
1 mole CO2 x (6 moles H2O/4 moles CO) = ??moles H2O
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