What is the area of the sector of a circle with θ=115° and a radius of 6 cm? Include π in your calculation.

(1 point)
Responses

A=76.97 cm2 A=76.97 cm2

A=113.10 cm2 A=113.10 cm2

A=6.02 cm2 A=6.02 cm2

A=36.13 cm2

1 answer

To find the area of a sector of a circle, you can use the following formula:

\[ A = \frac{\theta}{360^\circ} \times \pi r^2 \]

Where:

  • \( A \) is the area of the sector,
  • \( \theta \) is the central angle in degrees,
  • \( r \) is the radius of the circle.

Given \( \theta = 115^\circ \) and \( r = 6 \) cm, we can substitute these values into the formula:

\[ A = \frac{115}{360} \times \pi \times (6)^2 \] \[ A = \frac{115}{360} \times \pi \times 36 \] \[ A = \frac{115 \times 36}{360} \times \pi \] \[ A = \frac{4140}{360} \times \pi \] \[ A = 11.5 \times \pi \]

Now, calculating \( 11.5 \times \pi \):

Using \( \pi \approx 3.14 \) for estimation:

\[ A \approx 11.5 \times 3.14 \approx 36.13 \text{ cm}^2 \]

So, the area of the sector is:

\[ A \approx 36.13 \text{ cm}^2 \]

Thus, the correct response is:

A = 36.13 cm².